It is acquired from Dale on the firing range in Haven in the level Home. This redesigned Bullseye features a more blocky appearance and eliminates the sway indicators of the Resistance 2 model, instead featuring a projected holographic sight with indicators showing remaining ammunition and tags. It is very effective at short and medium range, and its fast rate-of-fire and large magazine size makes it ideal for close quarters combat; however, it tends to lose accuracy and power beyond short range.
If the "enemy secondary fire" cheat is on, you can be tagged by an enemy. The Resistance 3 Bullseye's bullets travel much faster than in previous games, being comparable in speed to the normal bullets fired by the M5A2 Folsom Carbine. While this makes it easier to hit enemies with the weapon, it also means you are no longer able to dodge Bullseye projectiles fired by enemy Hybrids. The Bullseye Trap feature is also removed. It is reclaimed by killing a Hybrid in the prison motorpool and then picking the Bullseye from it's corpse. R1 - Fires a volley of searing energy projectiles.
Marked II: The Resistance
R2 - Tags an enemy. If an enemy is tagged, all additional Bullseye shots will home in on the tagged enemy. The Bullseye is the first weapon obtained in Resistance: Burning Skies. The Bullseyes bears a cross between the Resistance: Fall of Man and Resistance 3 versions, using the latter game's holographic-style sights. Bullseye Tags are now fired using the touchscreen, and highlighting an enemy with the large cursor will ensure the tag hits them.
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The tag is always placed at the same point on an enemy; for example, it will always be on a Steelhead 's head. Drop by as soon as you can. We killed half a dozen stinks during the raid and took their weapons. They're calling one of them the "Bullseye" because it shoots real nice. We're talking at least projectiles per minute in the primary fire mode. Yeah, there's a secondary too. It allows you to fire homing tags. Once a stink has been tagged you can shoot it even if it's in cover or round a corner. Tell the guys.
Bullseyes should be standard in every cell. Never give up, and never give in. Touch and Hold the touchscreen to Tag an enemy. All your Bullseye shots will home in on your tagged enemy. Sign In Don't have an account? Start a Wiki. Contents [ show ]. What is the emf and internal resistance of the cell? A battery is connected in series with a rheostat and an ammeter. Find the emf and the internal resistance of the battery.
In the case of the very high resistance voltmeter we need to assume that the current is zero. In the case of a very low resistance ammeter, we can assume that the current that is flowing is the maximum current possible.
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An important thing to realise is that the potential difference you calculated or were given in previous examples is not the emf, it is the emf less that potential difference across the internal resistance. To emphasise that internal resistance is an extension to what you have already done we are going to take previous worked examples and consider the internal resistance of the battery. If the internal resistance did not behave like an ohmic resistor this wouldn't be possible but we won't deal with cases like that.
This is a very similar question to what you have seen earlier. This is to highlight the fact that the approach when dealing with internal resistance is built on all the same principles you have already been working with. We are given the potential difference across the cell and the current in the circuit, as well as the resistances of two of the three resistors. We can use Ohm's Law to calculate the potential difference across the known resistors.
The value of the emf can be calculated from the potential difference of the load and the potential difference across the internal resistance. Calculate the current through the cell and through each of the resistors.
We need to determine the current through the cell and each of the parallel resistors. We have been given the potential difference across the cell and the resistances of the resistors, so we can use Ohm's Law to calculate the current.
Marked II: The Resistance by Angela Caldwell
To calculate the current through the cell we first need to determine the equivalent resistance of the rest of the circuit. We know that for a purely parallel resistor configuration, the potential difference across the cell is the same as the potential difference across each of the parallel resistors. This total current through the battery is the current through the internal resistance of the battery.
Knowing the current and resistance allows us to use Ohm's law to determine the potential difference across the internal resistance and therefore the emf of the battery. We know that the emf of the battery is the potential difference across the terminal summed with the potential difference across the internal resistance so:. In this question you are given various pieces of information and asked to determine the power dissipated in each resistor and each combination of resistors. Notice that the information given is mostly for the overall circuit.
This is a clue that you should start with the overall circuit and work downwards to more specific circuit elements.
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Firstly we focus on the battery. We are given the power for the overall circuit as well as the current leaving the battery. We know that the potential difference across the terminals of the battery is the potential difference across the circuit as a whole. Remember that we are working from the overall circuit details down towards those for individual elements, this is opposite to how you treated this circuit earlier. We can treat the parallel networks like the equivalent resistors so the circuit we are currently dealing with looks like:.
If they didn't we would have made a calculation error. To determine the power we need the resistance which we have calculated and either the potential difference or current. The two resistors are in parallel so the potential difference across them is the same as well as the same as the potential difference across the parallel network. The difference is the potential difference across the internal resistance of the battery and we can use the known current and Ohm's law to determine the internal resistance:.
The headlamp and two IDENTICAL tail lamps of a scooter are connected in parallel to a battery with unknown internal resistance as shown in the simplified circuit diagram below. The resistance of the connecting wires may be ignored. How will the reading on the voltmeter be affected if the headlamp burns out?
The resistance increases and the current decreases. Test yourself now High marks in science are the key to your success and future plans.